12x^2-243=0

Solution for 12x^2-243=0 equation:

12x^2-243=0

a = 12; b = 0; c = -243;
Δ = b2-4ac
Δ = 02-4·12·(-243)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11664}=108$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-108}{2*12}=\frac{-108}{24}
=-4+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+108}{2*12}=\frac{108}{24}
=4+1/2
$